Una folla di sguardi vuoti

36

Problema

Dato nessun input scrivere un programma o una funzione che genera o restituisce la seguente stringa:

(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)

Regole

  • Vince il programma più breve.
  • Spazio bianco finale consentito.
  • Trailing newline ammessi.
  • Parametri non utilizzati per le funzioni consentite.
code-golf  ascii-art  kolmogorov-complexity 
— LiefdeWen
fonte
5
Nota: questa stringa è la concatenazione di sottostringhe di (<>.<>):"(<" + "(<>" + "(<>." + ... + "(<>.<>)" + "<>.<>)" + ">.<>)" + ... + ">)"
— JungHwan Min
2
Sarebbe stato un po 'meno "hardcode tutto il testo!" se fosse una folla più grande ...
— totalmente umana il
@totallyhuman Ci penserà la prossima volta
— LiefdeWen

Risposte:

13

SOGL V0.12 , 12 byte

pΙ2○3V?hG]‘Γ

Spiegazione:

pΙ2○3V?hG]‘   Push compressed string of the first half of the string (this is the kind of thing this compressor was made for)
           Γ  mirror, swap chars & palindromize with one character overlap

Provalo qui!

— dzaima
fonte
È bello vedere che hai un interprete online disponibile ora :)
— Emigna,
Come fai a fare questo? Ottimo lavoro però !!
— abhiagNitk il
18

05AB1E , 16 byte

"(<>.".∞ηJÀ24£.∞

Provalo online!

Spiegazione

"(<>."             # push this string
                   # STACK: "(<>."
      .∞           # intersected mirror
                   # STACK: "(<>.<>)"
        η          # compute prefixes
         J         # join to string
                   # STACK: "((<(<>(<>.(<>.<(<>.<>(<>.<>)"
          À        # rotate left
           24£     # take the first 24 chars
                   # STACK: "(<(<>(<>.(<>.<(<>.<>(<>."
              .∞   # intersected mirror
                   # STACK: "(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"
— Emigna
fonte
15

JS (Jsfuck), 10.614 byte

Non avevo accesso al sito web, ho dovuto capire tutto manualmente -.- 

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Spiegazione:

La maggior parte dei personaggi è relativamente semplice: per le parentesi che sto eseguendo 

   ([]["fill"]+[])[13] // '('

   ([]["fill"]+[])[14] // ')'

Il punto è ottenuto facendo creare a js un numero di notazione scientifica come 1.1e + 21 e prendendo il carattere punto dopo la conversione in una stringa

Le parentesi quadre sono più difficili, dobbiamo eseguire la funzione per creare una stringa di oggetto html in corsivo e rubare le parentesi angolari. Il trucco principale in questo è ottenere la 'c' per la parola corsivo, che richiede la costruzione di un'altra funzione per prendere la c da 'funzione'

C'è molto margine di miglioramento qui, principalmente su quali funzioni vengono utilizzate per ottenere le parentesi quadre. Ricordo anche un modo più semplice per ottenere il carattere 'c' se il corsivo è migliore, ma dovrei cercare i miei vecchi file per trovarlo

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Espandi frammento

— Rugnir
fonte
3
Questo sembra troppo lungo anche per JSFuck ma +1 per lo sforzo del foglio di farlo manualmente.
— F1Krazy,
Chiamo BS per farlo manualmente. Dovevi aver fatto qualcosa per automatizzare la generazione.
— Patrick Roberts,
10660 byte in realtà.
— Calcolatrice
6
@PatrickRoberts Scommetto che l'ha capito manualmente e ha usato i poteri di ctrlc e v
— bleh
1
@PatrickRoberts Non è un programma super difficile, è solo un caso per capire come costruire ogni personaggio. Come esempio di base, il modo per ottenere un carattere 't' è creare un array vuoto '[]', eseguire il cast su un numero per rendere il numero 0: '+ []' e quindi applicare l'operatore non ad esso per il cast a un vero booleano '! + []'. Quindi esegui il cast su una stringa, aggiungendo di nuovo un array vuoto e mettendolo tra parentesi per darci la stringa "true" '(! + [] + [])' E infine prendere la lettera zeroth con '(! + [] + []) [+ []] '
— Rugnir,
12

C # (Mono) , 54 52 byte

s=>"(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"

Provalo online!

-2 byte grazie a Kevin Cruijssen

RIP C #

— Skidsdev
fonte
Conosco la sensazione (Java). Tuttavia, è possibile salvare due byte. Il trailing ;non viene conteggiato per le risposte lambda. E ()può essere sostituito con un singolo carattere ( nulloggetto inutilizzato ). Meta post pertinente per il secondo.
— Kevin Cruijssen,
1
@KevinCruijssen Sì, ho specificato i parametri di funzione non utilizzati consentiti, quindi s=>è perfettamente soddisfacente.
— Liefde:
-1: Non è stato fatto alcuno sforzo per golfare la risposta in alcun modo.
— MechMK1
@ MechMK1 questo è il punto, è letteralmente il più possibile golfato in C #. L'output letterale della stringa è il modo più semplice per generare questa particolare stringa in questo particolare linguaggio. Vedi la risposta C # di
— Erlantz
@Skidsdev Continuo a considerare che è contro lo spirito di Code Golf, noioso da scrivere e noioso da leggere. Voglio dire, il mio voto non conta perché non partecipo attivamente, quindi non preoccuparti. Sono solo i miei 2 centesimi, per così dire.
— MechMK1,
7

V , 28 27 25 22 byte

3? 4? byte grazie a @KritixiLithos

i(<>.<>)òÙxlHÄ$xGòxÍî

Provalo online!

i(<>.<>)                'insert (<>.<>)
         ò        ò      'recursively
          Ù              'duplicate this (bottom line) down
           x             'delete the first character
            l            'and break when there's only one character left
             H           'go to the top of the buffer
              Ä          'duplicate that line up
               $x        'delete the last character
                 G       'and go back to the bottom of the buffer
                   x     'delete the extra ) left by the loop
                    Íî   'and remove all newlines
— nmjcman101
fonte
È possibile sostituire hxcon solo X.
— Kritixi Lithos,
Ed dkHxògJè 1 byte più corto di dkVHgJ0x.
— Kritixi Lithos,
Sì, anche la Íîcosa di DJ funziona
— nmjcman101,
Ricevo i(<>.<>)òÙxlHÄ$xGòddÍîper il 23
— Kritixi Lithos il
@KritixiLithos Ho letteralmente SOLO cambiato anche lXper xl: D
— nmjcman101
7

R , 42 byte

cat(substring('(<>.<>)',-4:6,2:12),sep='')

Programma abbastanza semplice che sfrutta il modo in cui funziona la sottostringa in R. Quindi substring('(<>.<>)',-4:6,2:12)produce il seguente vettore

> substring('(<>.<>)',-4:6,2:12)
 [1] "(<"      "(<>"     "(<>."    "(<>.<"   "(<>.<>"  "(<>.<>)" "<>.<>)"  ">.<>)"  
 [9] ".<>)"    "<>)"     ">)"

cat con un separatore vuoto lo invia a STDOUT nel formato richiesto.

Provalo online!

— MickyT
fonte
5

TrumpScript, 70 Bytes

I know, it's a boring solution.

say "(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"
America is great
— Dust
fonte
Well done, nonetheless.
— Adam
4

Brachylog, 14 bytes

"(<>.<>)"aᶠckb

Try it online!

"(<>.<>)"           #   string
         aᶠ         #       get all Affixes (pre- and suffixes)
           c        #       Concatenate
            kb      #       remove last (Knife) and first (Behead)
— Kroppeb
fonte
As of now the full face seems to get duplicated, but you can fix it by just changing the ᶠ into a ᵘ.
— Unrelated String
3

C (gcc), 59 57 bytes

2 4 bytes less than a simple puts() solution. There is sure to be some elegant recursive solution, but so far the overhead becomes too large at every attempt.

f(i){for(i=1;i++<12;)printf("%.*s",i,"(<>.<>)"+i/7*i%7);}

Try it online!

— gastropner
fonte
3

Brainfuck, 198 175 167 Bytes

I have never done a codegolf, so this is my first one. Feedback is highly appreciated.

++++[>+++++<-]>[>++>+++>+++>++>++[<]>-]>.>.<.>.>++.<<.>.>.>>++++++.<<<<.>.>.>>.<<<.<.>.>.>>.<<<.>.<<.>.>.>>.<<<.>.>+.<<.>.>>.<<<.>.>.<.>>.<<<.>.>.>.<<<.>.>.<<.>.>.<.>.

Try it online!

I went for the most obvious solution in my opinion. First, I set cells 1-5 to one of the letters "().<>". Then I just go to the right cells and output the character.

UPDATE: I changed the order in which the characters appear on the "tape" making the program way shorter and more efficient.

UPDATE 2: Just revisited my post after a while and realized, that using a shorter sequence for setting up the cells I could save some bytes.

— Dust
fonte
Welcome to PPCG! :)
— Shaggy
Nice, first answer, usually answers that are not immediately apparent how they work need an explanation but this challenge is pretty trivial so not really needed. But if you do a 1200 bytes brainfuck in the future just a simple explanation goes a long way.
— LiefdeWen
I will be sure to do that in the future.
— Dust
Ok, I added a short (and kinda bad) description of my code.
— Dust
2

JavaScript, 47 bytes

g=(i=2)=>i>12?'':'(<>.<>)'.slice(i-14,i)+g(i+1)
f=(i=11)=>i?f(i-1)+'(<>.<>)'.slice(i-13,i+1):''

// Both of the above work and are the same size

document.write('<pre>Actual g(): ' + g() + '\nActual f(): ' + f() + '\nExpected:   (<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)</pre>');
Expand snippet

Uses the same method as Rod's Python answer.

— Artyer
fonte
2

Charcoal, 20 bytes

Ａ(<>ι(<ιι.ι.<ι.ιι.‖Ｂ

Try it online!

Thanks to Destructible Lemon for noticing a pattern (-4).

AST:

Program
├Ａ: Assign
│├'(<>': String '(<>'
│└ι: Identifier ι
├Print
│└'(<': String '(<'
├Print
│└ι: Identifier ι
├Print
│└ι: Identifier ι
├Print
│└'.': String '.'
├Print
│└ι: Identifier ι
├Print
│└'.<': String '.<'
├Print
│└ι: Identifier ι
├Print
│└'.': String '.'
├Print
│└ι: Identifier ι
├Print
│└ι: Identifier ι
├Print
│└'.': String '.'
└‖Ｂ: Reflect butterfly
 └Multidirectional

What ‖Ｂ does is basically visually palindromize canvas.

— Erik the Outgolfer
fonte
Explanation please.
— CalculatorFeline
@CalculatorFeline Added AST as returned by -a.
— Erik the Outgolfer
Huh. That was more useful than I thought.
— CalculatorFeline
I think this would be clearer even if you just added that print is implicit with objects
— Destructible Lemon
@DestructibleLemon But the AST already has the Prints in there, not sure what you mean.
— Erik the Outgolfer
2

C (gcc), 61 bytes

I know this is lame but it's much shorter than my other solution...

f(){puts("(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)");}

C (gcc), 103 bytes

Here's a version where I'm trying to be somewhat tricky...

char*e="(<>.<>)<>.<>)>.<>).<>)<>)>)";f(i,n){for(n=2;n<8;n++)for(i=0;i<n;i++)putchar(e[i]);puts(&e[i]);}

C (gcc), 117 115 bytes

A recursive version that's fully tricky...

char*e="(<>.<>)";main(i,j){if(i<6){for(++i,j=0;j<i;putchar(e[j++]));main(i);}else if(i<12)printf(e+i++-6),main(i);}

Try it online!

— cleblanc
fonte
1
Please also share your none-hardcoded solution. Despite being longer I'm sure it's much more interesting than this trivial one.
— Laikoni
2

A crowd of blank stares watching Batman in honor of Adam West...

C# (.NET Core), 393 bytes

s=>{string b="NanananaNanaBATMAN!NanaBATMAN!NANANanaBATMAN!NANAnanaNanaBATMAN!NANABATMAN!NanaBATMAN!NANABATMAN!naNABATMAN!NANABATMAN!naNANAnaNANABATMAN!naNANANABATMAN!naNABATMAN!naNANAnanaNA",r="",t;for(int i=0;i<176;)if(b[i]=='B'){r+="<>";i+=7;}else{t=b.Substring(i,4);if(t=="Nana")r+="(";else if(t=="nana")r+="<";else if(t=="NAna")r+=">";else if(t=="NANA")r+=".";else r+=")";i+=4;}return r;}

Try it online!

— Charlie
fonte
2

q, 29 bytes

raze"(<>.<>)"{(y-5)_x}/:(!)11

-2 bytes thanks to streetster

EDIT for explanation:

Language is right to left interpreted.

How it works

raze"(<>.<>)"{(y-5)_x}/:(!)11
                        (!)11 /yields indices [0-10], right parameter of function (y)
                      /:      /each right: loop right parameter of a dyadic function
             {       }        /function
    "(<>.<>)"                 /left parameter of function (x)
              (y-5)           /subtract 5 from y (indices)
                   _          /remove first y chars from x, or last y chars if negative
raze                          /flatten string output to produce the final string
— B.Wong
fonte
4
An explanation here would be great.
— Gryphon - Reinstate Monica
1
You can remove the space before the _x for 1 byte, and change til 11 to (!)11 for another 1 byte saving = 2 bytes saved :)
— streetster
@streetster great stuff :)
— B.Wong
2

Haskell, 55 45 bytes

map take[2..7]++map drop[1..5]>>=($"(<>.<>)")

Try it online!

First Haskell answer to beat the hardcoded solution!

Explanation

The way this answer works is by building a list of functions to be applied to the string (<>.<>). First we build the left and center with

map take[2..7]

which gives us all the prefixes from size two to seven. Then we build the right with

map drop[1..5]

which gives us all the suffixes from size six to two.

Once we have the list of functions we use a monadic bind (>>=) which is just concatMap but shorter. The function we concatmap with is ($"(<>.<>)") which applies the input to the string (<>.<>).

This makes the string.

— Wheat Wizard
fonte
1

Java 8, 52 bytes

x->"(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"

Boring, but there isn't any way to make this shorter in Java.. Just initializing a temp String is already 11 bytes.. (String t="something";), and using substring a couple of times certainly costs too many bytes..

Shortest alternative to a literal return is probably this (58 bytes):

x->"(<(x(x.(x.<(x.x(x.x)x.x)>.x).x)x)>)".replace("x","<>")

Try it here.

— Kevin Cruijssen
fonte
Also works in JavaScript, using a "fat arrow" function (=>) if you want to add it.
— Shaggy
@Shaggy Nah, you can keep your JavaScript answer if you want. The same applies to C# which also already has a separate answer.
— Kevin Cruijssen
1

Python 2, 57 bytes

print''.join("(<>.<>)"[max(0,n-5):n+2]for n in range(11))

I say it looks like a gang of owls peeking out behind their leader. Just saying.

— Daniel
fonte
1

brainfuck, 245 210 bytes

Golfing in progress.

>++++++++[<+++++>-]>++++++[<++++++++++>-]>++++++[<++++++++++>-]<++>>++++++++[<+++++>-]<++++++<<<.>.<.>.>.<<.>.>.>.<<<.>.>.>.<<.<.>.>.>.<<.>.<<.>.>.>.<<.>.<<+.>.>.>.<<.>.<<.>>.>.<<.>.<<.>>>.<<.>.<<.>.>.<<.>>.<<.

Try it online!

— totallyhuman
fonte
1

Haskell, 95 bytes

import Data.List
import Control.Arrow
concat$tail$init$uncurry(++)$inits&&&tail.tails$"(<>.<>)"

This is far longer than the 49 bytes necessary for a string literal with the output, but the best I could do to utilise the structure. As usual, I love arrows, and inits &&& tails does produce a tuple of the list of leading substrings and the list of trailing substrings of the input. Then those two tuple elements are put together in one list by passing the tuple to ++, and that list is concatenated to one large string. The tail and init calls avoid duplicating the (<>.<>) in the middle (one generated by inits, the other by tails) and drop the unwanted parenthesis from the start and end, taking only substrings of length 2 or more into account.

— Bergi
fonte
Can you please add an explanation?
— CalculatorFeline
@CalculatorFeline Done
— Bergi
1

Jelly, 18 bytes

“(<>.<>)”ḣJœ|ṫJ$ḊṖ

Try it online!

How it works

“(<>.<>)”ḣJœ|ṫJ$ḊṖ  Main link. No arguments.

“(<>.<>)”           Set the argument and return value to s := "(<>.<>)".
          J         Yield all indices of s, i.e., [1, 2, 3, 4, 5, 6, 7].
         ḣ          Dyadic head; yield s's prefixes of lengths 1 to 7.
               $    Combine the two links to the left into a chain.
              J         Indices; yield [1, 2, 3, 4, 5, 6, 7].
             ṫ          Dyadic tail; yield s's postfixes of lengths 1 to 7.
           œ|       Multiset union; concatenate the results to both sides,
                    discarding the copy of s. (s is both a prefix and a postfix.)
                Ḋ   Dequeue; remove the first prefix, i.e., "(".
                 Ṗ  Pop; remove the last postfix, i.e., ")".
— Dennis
fonte
1

C (clang), 62 61 bytes

main(n){while(write(++n<13,n/7*(n-7)+"(<>.<>)",n/7?14-n:n));}

This terminates only after timing out on TIO because the write to standard input fails, but it will terminate in a terminal. The program relies on a specific order of evaluation (undefined behavior) and won't work with, e.g., gcc.

Thanks to @Steadybox for an idea that saved a byte!

Try it online!

Verification

$ cat crowd.c
main(n){while(write(++n<12,n/7*(n-7)+"(<>.<>)",n/7?14-n:n));}
$ clang -o crowd crowd.c 2> /dev/null

$ ./crowd 0> /dev/null
(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)

Alternate version, 62 bytes

main(n){while(++n<13)write(1,n/7*(n-7)+"(<>.<>)",n/7?14-n:n);}

At the cost of one more byte, the solution becomes a lot more portable.

Try it online!

— Dennis
fonte
1
60 bytes as a function, but it's probably not reliable.
— Steadybox
— Dennis
@Dennis Yeah, the (< is missing there.
— Erik the Outgolfer
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