Crea un programma che quando viene eseguito visualizza il testo seguente:
)-*-*-*^_^*-*-*-(
| Welcome User! |
)-*-*-*^_^*-*-*-(
Usa qualsiasi funzione o lingua per rispondere a questo, divertiti. Il codice più corto vince
Crea un programma che quando viene eseguito visualizza il testo seguente:
)-*-*-*^_^*-*-*-(
| Welcome User! |
)-*-*-*^_^*-*-*-(
Usa qualsiasi funzione o lingua per rispondere a questo, divertiti. Il codice più corto vince
Risposte:
Salvato 2 byte grazie a @Shaggy
[U="){"-*-*-*^_"ê}("`| WelÖ U r! |`U]·
[U="){"-*-*-*^_"ê}("`| WelÖ U r! |`U]·
[ ] // Create a new array
U= // Variable U =
") // ")
{ } // Evaluate everything in curley-brackets as code
"-*-*-*^_"ê // "-*-*-*^_" mirrored -> -*-*-*^_^*-*-*-
(" // ("
* Now we have [U=")-*-*-*^_^*-*-*-("]
`| WelÖ U r! |` // "| Welcome User! |" decompressed by `...`
U // ")-*-*-*^_^*-*-*-("
* Now we have [")-*-*-*^_^*-*-*-(","| Welcome User! |",")-*-*-*^_^*-*-*-("]
· // Split with new-lines
PRINT')-*-*-*^_^*-*-*-(
| Welcome User! |
)-*-*-*^_^*-*-*-('
SQL consente di dividere i valori letterali delle stringhe su righe, quindi vengono conteggiati i ritorni.
Lavorando su una soluzione procedurale, ma dubito che ne troverò uno sotto i 60 anni.
Nuova modifica : trovato un semplice REPLACEche lega la banale soluzione:
PRINT REPLACE('1
| Welcome User! |
1',1,')-*-*-*^_^*-*-*-(')
Si scopre che REPLACE farà una conversione implicita di un numero in una stringa, quindi questo mi permette di salvare 2 caratteri eliminando le virgolette attorno al mio carattere sostitutivo.
Cercare di inserirlo in una variabile è troppo lungo, a causa del sovraccarico dei DECLARE(69 byte):
DECLARE @ CHAR(17)=')-*-*-*^_^*-*-*-('PRINT @+'
| Welcome User! |
'+@
a="\n)-*-*-*^_^*-*-*-(\n"
print a+'| Welcome User! |'+a
Abbastanza semplice. Include le nuove righe principali e finali.
main(i){for(;printf(")-*-*-*^_^*-*-*-(")&i--;puts("\n| Welcome User! |"));}
#define P puts(")-*-*-*^_^*-*-*-(") f(){P;puts("| Welcome User! |");P;}
00000000: d3d4 d502 c1b8 f838 30ad abc1 55a3 109e .......80...U...
00000010: 9a93 9c9f 9baa 105a 9c5a a4a8 50c3 a589 .......Z.Z..P...
00000020: ae06 00bd 4d85 9835 0000 00 ....M..5...
-3 byte grazie a Emigna
")-*-*-*^_".∞D”|‡Ý‚Ý! |”s»
")-*-*-*^_".∞D”|‡Ý‚Ý! |”s»
")-*-*-*^_" # Push )-*-*-*^_
.∞ # Intersected mirror (results in )-*-*-*^_^*-*-*-( )
D # Duplicate top of stack
”|‡Ý‚Ý! |” # Pushes | Welcome User! |
s # Swap top items on stack
» # Join on newlines
.∞invece diû¨'(«
")-*-*-*^_"in ')„-*Є^_J. :)
print(")-*-*-*^_^*-*-*-(\n| Welcome User! |\n)-*-*-*^_^*-*-*-(")
Create a program
alert(`${s=")-*-*-*^_^*-*-*-("}
| Welcome User! |
${s}`)
_=>(s=")-*-*-*^_^*-*-*-(")+`
| Welcome User! |
`+s
-2 byte grazie a Rick Hitckcock
alert? Salva qualche byte usando una funzione.
alertin un .jsfile ed eseguilo nel tuo browser, verrà eseguito.
_=>(s=")-*-*-*^_^*-*-*-(")+\ n | Benvenuto utente! | \ n+s
main(){char*S=")-*-*-*^_^*-*-*-(";printf("%s\n| Welcome User! |\n%s",S,S);}
m=")-*-*-*^_^*-*-*-(";main(){printf("%s\n| Welcome User! |\n%s",m,m);}
_=>")-*-*-*^_^*-*-*-(\n| Welcome User! |\n)-*-*-*^_^*-*-*-("
Due al prezzo di uno:
s/^/)-*-*-*^_^*-*-*-(/p
x
s/^/| Welcome User! |/p
x
s/^/)-*-*-*^_^*-*-*-(\n| Welcome User! |/p
s/\n.*//
a=')-*-*-*^_^*-*-*-(';disp([a;'| Welcome User! |';a])
MATLAB / Python? This is definitely not valid python.
disp Matlab will show leading ans = \n.
disp there as it won't conform to the exact output.
ans = is not disallowed you can save 6 bytes.
print$\=")-*-*-*^_^*-*-*-(","
| Welcome User! |
"
Uses the fact that $\ is implicitly printed after each print.
say?
print with say isn't really where the point of golfing lies in my opinion. But I'm not on any crusade to stop using say though; I let everyone do as they like, and everyone is happy :)
_^×*-³(⸿emocleW |‖B¬J¹¦¹ User!
Try it online! Link is to verbose version of code. Explanation:
_^ Print("_^");
×*-³ Print(Times("*-", 3));
(⸿emocleW | Print("(\remocleW |");
Prints the mirror image of the top left portion of the output.
‖B¬ ReflectButterfly(:¬);
Reflects down and to the left to create the top and bottom lines and the left of the middle line.
J¹¦¹ JumpTo(1, 1);
User! Print(" User!");
Fixes up the middle line.
func main(){var a string=")-*-*-*^_^*-*-*-(\n";Printf(a+"| Welcome User! |\n"+a)}
fmt import, sorry.
tellraw @a {"text":")-*-*-*^_^*-*-*-(\n| Welcome User! |\n)-*-*-*^_^*-*-*-("}
22#)[#-#*]"^_^"[#*#-]#(V"
| Welcome User! |
"R!&@v&@R&@
It's 2 bytes shorter than hardcoding the output.
22 Push 2 2s to the stack
These are used for loop counting
#) Push )
[#-#*] Push -* 3 times, using one of the 2s
"^_^" Push ^_^
[#*#-] Push *- 3 times, using the remaining 2
#( Push (
V Create a new stack
"
| Welcome User! |
" Push \n| Welcome User! |\n to the new stack
R!&@ Return to main stack, print entire stack without popping
v&@ Switch to 2nd stack, pop and print stack
R Return to main stack, pop and print stack
<?=$a=")-*-*-*^_^*-*-*-(","\n| Welcome User! |\n$a";
@SET b=@ECHO )-*-*-*^^^^_^^^^*-*-*-(
%b%
@ECHO ^| Welcome User! ^|
%b%
I mostly enjoy this one because all the escape characters make the emoticon ^_^ look like an adorable Lovecraft abomination ^^^^_^^^^
é)8a-*r(ãhR^_^Äo| Welcome User! |
Hexdump:
00000000: e929 3861 2d2a 1b72 28e3 6852 5e5f 5e1b .)8a-*.r(.hR^_^.
00000010: c46f 7c20 5765 6c63 6f6d 6520 5573 6572 .o| Welcome User
00000020: 2120 7c ! |
Explanation:
é) " Insert a '('
8a " Append 8 copies of the following:
-*<esc> " '-*'
r( " Replace the last character on this line with '('
ãh " Move to the middle of this line
R " And write the following text over the existing text:
^_^<esc> " '^_^'
Ä " Duplicate this line
o " On a new line:
| Welcome User! | " Write the whole middle line
It's boring, but I just cant find a way to creat )-*-*-*^_^*-*-*-( or | Welcome User! | in less bytes than just copying the strings.
J")-*-*-*^_^*-*-*-("J"| Welcome User! |"J
Explanation:
J")-*-*-*^_^*-*-*-(" # J = ")-*-*-*^_^*-*-*-("
J # Print J with new line
"| Welcome User! |" # Print "| Welcome User! |" with new line
J # Print J with new line
)-*-*-*\^_\^*-*-*-(
^*1//.+/gS"
| Welcome User! |
"
)-*-*-*\^_\^*-*-*-(
^ Give the stack-string this value ")-*-*-*^_^*-*-*-(\n"
*1 Append 1 duplicate of the stack-string to itself
stack-string: ")-*-*-*^_^*-*-*-(\n)-*-*-*^_^*-*-*-("
//.+/g Get matches of /.+/g and set the stack-array to this result
stack-array: [")-*-*-*^_^*-*-*-(",")-*-*-*^_^*-*-*-("]
S"
| Welcome User! |
" Join the stack-array on "\n| Welcome User! |\n" and
set the stack-string to this result
f=")-*-*-*^_^*-*-*-("
echo "$f
| Welcome User! |
$f"
i)^[8a-*^[r(9hR^_^^[Yo| Welcome User! |^[p
Shoutout to the homies in the comments
Original:
i)-\*^[vhyl2pa^_^\*-^[vhyl2pa(^[Vyo| Welcome User! |^[p
Where ^[ is the ESC key
i)-*-*-*^_^*-*-*-(^] is much shorter for constructing the top line. Also, Y is equivalent to Vy
i)^]8a-*^[r(9hR^_^^[
^[ at the end. YPo| Welcome User! |
P was a thing. That's awesome though. Thanks!
x->"".format("%s| Welcome User! |\n%<s",")-*-*-*^_^*-*-*-(\n")
Or as full program (110 bytes):
interface A{static void main(String[]a){System.out.printf("%s| Welcome User! |\n%<s",")-*-*-*^_^*-*-*-(\n");}}
Surprised there wasn't a Java answer yet.