Malbolge , 20775 e 2334 byte
Probabilmente non ho battuto nessuno con esso, ma è stato incredibilmente divertente da realizzare.
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Se la sfida non ha richiesto l'arresto ad un certo punto (ad es. Eof), diventa piuttosto banale, segnando 2334 byte :
bP&A@?>=<;:9876543210/.-,+*)('&%$T"!~}|;]yxwvutslUSRQ.yx+i)J9edFb4`_^]\yxwRQ)(TSRQ]m!G0KJIyxFvDa%_@?"=<5:98765.-2+*/.-,+*)('&%$#"!~}|utyrqvutsrqjonmPkjihgfedc\DDYAA\>>Y;;V886L5322G//D,,G))>&&A##!7~5:{y7xvuu,10/.-,+*)('&%$#"yb}|{zyxwvutmVqSohmOOjihafeHcEa`YAA\[ZYRW:U7SLKP3NMLK-I,GFED&%%@?>=6;|9y70/4u210/o-n+k)"!gg$#"!x}`{zyxZvYtsrqSoRmlkjLhKfedcEaD_^]\>Z=XWVU7S6QPON0LKDI,GFEDCBA#?"=};438y6543s1r/o-&%*k('&%e#d!~}|^z]xwvuWsVqponPlOjihgIeHcba`B^A\[ZY;W:UTSR4PI2MLKJ,,AFE(&B;:?"~<}{zz165v3s+*/pn,mk)jh&ge#db~a_{^\xwvoXsrqpRnmfkjMKg`_GG\aDB^A?[><X;9U86R53ONM0KJC,+FEDC&A@?!!6||3876w4-tr*/.-&+*)('&%$e"!~}|utyxwvutWlkponmlOjchg`edGba`_XW\?ZYRQVOT7RQPINML/JIHAFEDC&A@?>!<;{98yw5.-ss*/pn,+lj(!~ff{"ca}`^z][wZXtWUqTRnQOkNLhgfIdcFaZ_^A\[Z<XW:U8SRQPOHML/JIHG*ED=%%:?>=~;:{876w43210/(-,+*)('h%$d"ca}|_z\rqYYnsVTpoRPledLLafIGcbE`BXW??TY<:V97S64P31M0.J-+G*(DCB%@?"=<;|98765.3210p.-n+$)i'h%${"!~}|{zyxwvuXVlkpSQmlOjLbafIGcbE`BXW??TY<:V97S64P31M0.J-+G*(D'%A@?"=<}:98y6543,1r/.o,+*)j'&%eez!~a|^tsx[YutWUqjinQOkjMhJ`_dGEaDB^A?[><X;9U86R53O20LKJ-HG*ED'BA@?>7~;:{y7x5.3210q.-n+*)jh&%$#"c~}`{z]rwvutWrkpohmPkjihafI^cba`_^A\[>YXW:UTS5QP3NM0KJ-HGF?D'BA:?>=~;:z8765v32s0/.-nl$#(ig%fd"ca}|_]yrqvYWsVTpSQmPNjMKgJHdGEa`_B]\?ZY<WVUTMR5PO20LK.IHA))>CB%#?87}}49zx6wu3tr0qo-nl*ki'hf$ec!~}`{^yxwvotsrUponQlkMihKIe^]EEZ_B@\?=Y<:V97S64P31M0.J-+GFE(C&A@?8=<;:{876w43s10qo-&%kk"'hf$ec!b`|_]y\ZvYWsVTpSQmlkNiLgf_dcba`C^]\?ZY;WV97SLK33HM0.J-+G*(D'%A$">!};|z8yw543t1r/(-,+*)(i&%fd"!~}|_t]xwvutslqTonmPkjLhKIeHFbEC_^A?[TSX;9UT7R4JIN1/K.,H+)E(&B%#?"~<}{987x/4u21rp(',mk)jh&%fd"yx}`^z][wZXtWUTTinmPkMcbgJHGG\a`C^@VUZ=;::OTS6Q3IHMLK.-B+FE(CBA##8~~5:98yx5.3t10q.-,+*ki'~}eez!~}`_zyxqvYtsVqpoQQfkjMhJ`_dGEaDBAAV[Z=;WPOT7544INM0K-CBG*(D'%A$">!};|z8yw5vt210qp-,+*#j'&g$#"!~a_{ts[[putsVUponmlkdMhgJedcEEZ_^A\>TSXWV98SRQPONMFK.IHGFE'=BA@?!7~5:9816/4u21r/.-,+lj(!~ff{"!~a`uz]xwvYtsUqTRnQONNchgJHd]\aDBAAV[Z=;WPOT7544INM0.JCBG*(''<A@#!=65:{yxx/43tr0)(-nlkk"'&ge#zy~}|_ty\wvYWmlqTRnmPkMcbgJHdcFaCYX]@>==RWV97SLKP31M0.J-+G*(D'%A$">!}||3876wv-t10/p-,l*)(i~%fddcx}`{zy\wvXtWUqTRnQOkjMhJ`_dGEDDY^]@[=SRW:877LQP3N0FEJ-+**?DC&A#98=~|{{276w4t,+0qonn%*)j'g}|#db~a_^^sxwvYXmrUponQlkMiLJfIGFF[`_B@\UTY<:99NSR53OHGL/-,,AFE(&B;:?"~}}498yw5.-2sq/.-n%l)('&%$e@b>,+^^:87Z5n"!10/QP-kMv(gf%Gc543}|0{[-YXu)t87L5]Ol~jjiz++evbaa`M^!=Z|kWWD05S3?O*)o'JJH)F!~f1TAy>,<^]:xJ6YXmlD0SAQPk+vKaJ%%F5ECCX|zz=xRQ
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Spiegazione
Mi è stato chiesto di spiegare come funziona il programma. Prenderò il secondo in quanto è molto più semplice spiegarlo rispetto al primo, ma il modo in cui entrambi funzionano è molto simile.
Cominciamo le cose con la decrittazione del codice. Come qualcuno nei commenti ha fatto prima di iniziare a lavorare sulla spiegazione, quindi ti consiglio davvero di verificarlo.
Ciò non semplifica la lettura del programma, ma prima di passare direttamente al codice, rivediamo le basi di Malbolge.
La macchina virtuale si riferiscono al trits ( tri cifre nario s ). Ogni parola della macchina ha una larghezza di dieci trit, quindi varia da 0 a 2222222222t (= 59048d). Ogni posizione di memoria contiene una parola macchina; anche gli indirizzi sono larghi di una sola parola. Sia i dati che il codice condividono lo stesso spazio di memoria.
Esistono tre registri, ognuno dei quali contiene una parola macchina, inizialmente 0: il registro codici C che è un puntatore all'istruzione che sta per essere eseguita, il registro dati D utilizzato per la manipolazione dei dati e l'accumulatore A usato anche da diversi istruzioni per manipolare i dati.
Se l'istruzione da eseguire non è compresa nell'intervallo 33-126, l'esecuzione si interrompe (l'interprete di riferimento si blocca in questo caso a causa di un errore). Altrimenti, al fine di determinare l'istruzione effettiva da eseguire, il valore indicato dal registro C viene aggiunto al registro C stesso e il risultato viene diviso per 94, prendendo il resto.
Ecco una tabella di tutte le possibili istruzioni.
Ora che il codice è più comprensibile ed è effettivamente possibile dire cosa sta succedendo lì, possiamo saltare all'idea generale di ciò che sta accadendo lì.
Senza alcun salto, la programmazione di Malbolge è praticamente banale. Tuttavia, quando si utilizzano i salti, è necessario eseguire un'attività di decrittografia prima di eseguire nuovamente questo codice. Ogni volta che un'istruzione viene eseguita, viene immediatamente crittografata, quindi non si comporta in questo modo come prima.
Per illustrare la soluzione alternativa, diamo un'occhiata al programma normalizzato per gatti Malbolge:
jpoo*pjoooop*ojoopoo*ojoooooppjoivvv
o/i<iviv
i<vvvvvvvvvvvvv
oji
Come puoi vedere, nella seconda riga abbiamo istruzioni /
e <
istruzioni per le cose di I / O. Utilizzando il fatto che C
register è il puntatore dell'istruzione, possiamo modificarlo usando l' i
istruzione creando in modo efficace un ramo. Prima che avvenga il ramo, dobbiamo decrittografare le istruzioni che a pochi cicli di distanza leggono e scrivono l'output da e verso TTY, combinato con un salto. Poiché non esiste un modo reale per archiviare le costanti in modo efficace, dobbiamo incorporare molte istruzioni non correlate e utilizzare il loro valore per calcolare le altre costanti necessarie (utilizzando il fatto che Malbolge non separa programma e dati)
Nota: parti di questa risposta sono state tratte dalla pagina Malolge wiki di Esolang concessa in licenza sotto CC0 - link .
Forse, potresti voler controllare la mia altra risposta con Seed