Scrivi un programma che, per i numeri da 1 a 255, stampa il codice BF che produrrà il numero dato in qualche byte dell'array, più una nuova riga.

Ad esempio, le prime quattro righe dell'output potrebbero (e molto probabilmente saranno):

+
++
+++
++++

Il vincitore sarà il più piccolo: source code + output(in byte).

Chiarimenti e revisioni :

• I programmi BF usano celle avvolgenti.

• Il programma di output BF deve terminare con l'unica cella diversa da zero che è la cella contenente il numero.

• I programmi devono essere emessi in ordine crescente.

• L'output di un programma per 0 è facoltativo.

• Non sono consentiti puntatori di dati negativi. <al primo puntatore non farà nulla. (lascia un commento se sarebbe più appropriato farlo lanciare)

Perl 6 , 224 + 3964 = 5834 4188 byte

map {say (.[0]~'['~.[3]~'>'~.[1]~'<]')x?.[1],'>'x?.all,.[2]}o*.min({$_>>.abs.sum+6*?.[1]})>>.&{<- +>[.sign>0]x.abs},classify({0+|(grep(*%%1,(((256 X*^4)X+.[0]%256)X/-.[3]))[0]*.[1]+.[2])%256},[X] |(^27-13 xx 3),-7..-1){^256}

Provalo online! (può timeout. Cambia ^27-13in^25-12 per velocizzare leggermente a scapito di un output extra)

Emette il codice più breve nel modulo *>[*>*<]>*, dove ognuno *è un certo numero di +s o -s. Ci sono alcune modifiche extra come rimuovere il loop se non è necessario, così come i finali >.

Per quanto ne so, l'output è il più golfato per questo particolare formato.

Spiegazione:

([X] |(^27-13 xx 3),-7..-1)        # Define the search space as the cross product of:
                                        # -13 to 13 for:
                                            # Initialisation     +++>
                                            # Change in target   [*>+++<]
                                            # Last change        >+++
                                        # And -7 to -1 for the change in start [-->*<]
  .classify({                  })  # Group them by calculating
                  (256 X*^4)                         # Each of the multiples of 256
                 (          X+.[0]%256)              # Plus the initialisation
                (                      X/-.[3])      # Divided by the change in start
      grep(*%%1,                               )     # Filter out the whole numbers
                                                [0]  # And take the first value
          # This is the amount of times the inner loop will execute
          # Being Nil, converted to 0 if it is an infinite loop
      *.[1]              # Multiply by the change to the target cell
           +.[2]         # And add the final section
     (          )%256    # And modulo the whole lot by 256
                     +|0 # And floor it just to keep the .0 out
classify(                   ){^256}     # Take the corresponding groups in order
   .map(                             )  # And map each to
        *.min({                    })   # Find the minimum by:
               $_>>.abs.sum             # The sum of the absolute values    
                           +6*?.[1]     # Plus 6 if it loops
      >>.*{                   }    # Then map each value to
           <- +>[.sign>0]          # + or - depending on the sign
                         x.abs     # Repeated by the absolute value 
   {                    }o              # And pass this to the next code block
    say                       # Print
        (.[0]~'['~.[3]~'>'~.[1]~'<]')             # The loop section
                                     x?.all       # If it is needed
                                           ,.[2]  # And the final part

Malbolge , 28 743 byte + 7 166 di output

Non troppo creativo, no? Lavorerò sul golf questo cattivo ragazzo.

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Provalo online!

Brainfuck, 77 75 73 + = 32894 32967 32969 32971 byte

++++++[->+++++++<]>+>++++++++++>+[>+[-<<<.>>>]<<.>[->+>+<<]>>[-<<+>>]<<+]

Provalo online!

l'output è il più semplice possibile

+
++
+++
++++
...

spiegazione:

++++++[->+++++++<]>+ set cell 2 to 43 (ascii of plus)
>++++++++++ set cell 3 to 10 (ascii of new line)
>+ set cell 4 to 1
[
    >+ increment cell 5
    [
        -<<<.>>> decrement cell 5 and print a plus (content of cell 2)
    ] until cell 5 == 0
    <<.> print a new line (content of cell 3)
    [
        ->+>+<< move value of cell 4 to cell 5 & 6, setting cell 4 to 0
    ]
    >> goto cell 6
    [
        -<<+>> move it's value to cell 4, setting cell 6 to 0
    ]
<<+ increment cell 4
] exit when cell 4 goes beyond 255 because cell contains C uchar meaning 255 + 1 == 0

Stax , punteggio 4751 4783 (812 byte + 3971)

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Esegui ed esegui il debug

Ho iniziato con i programmi pubblicati ottimali .
Ho usato un po 'di regex-fu, per limitarlo ai programmi più brevi che usano al massimo 2 celle. Quindi ho tagliato qualsiasi carattere <o coda >. Penso che questo sia un modo forse conservativo per garantire che non ci siano celle diverse da zero al termine del programma. Poi l'ho eseguito attraverso un programma stax sperimentale che ho scritto per generare programmi stax per l'output fisso di tipo kolmogorov.
Questo programma funziona applicando ripetutamente le sostituzioni di stringhe. Ad ogni passaggio, cerca una sottostringa di lunghezza> 1 che si verifica più frequentemente e la sostituisce con un carattere non utilizzato.

Carbone di legna , 707 698 410 + 3627 = 4334 4325 4037 byte

ＵＴ≔”}⊞Ｊ5±)↷γ²⁼⎇⦃<✂f^⊗Ｌ…¬⁻←«θ↥v⊙^≔¶υＳψVτ16⁷·9I⌕↘;⦃@Pmt↙ ｜TＬ ‹.bＥ^↷Ａm⟧←⪫✂«ＧＩχ¤⟲V⁻PÀ$χ¹'$↙‖%S³6◧N=$kＨＩpQ×ïu｜%÷I↖➙⁸≔Wλ¹ê8⌕dNK‽3H∨↥γh➙↘⊙⊕“~Oj↨-⬤…⊟⁺§◨ＣＢ℅Ｐ⌕KＮＥAR№K⬤Ｘ"¬Ｓ⎇⧴V⁻±6⁼✂kι×ＣÀ⊞‴≡w↓γ=`→P5η1Ｃ⊖ＯSoNυs⊘$M↙êαη↖φ¡¿:θ-γ“rＪW%Ｅ(7<w¤Ｕφ´ρＨπ←SＸ↔τ↧%<Ｔº⎇0gθμ↓⌕；σw⌈pL;Ｙ↘ＹΠ⊙>ξＬzλ↓⁸ι⎚｜⌕ΠP″M³⧴⬤¦➙⟧⌕/δ；↥⁻ºJK⌊≡<⊖λ✳Ｊκ⟲➙ξ⭆｜^Σ*βＭπ⍘⊟；ÀＵ÷‹⭆◧�ωκ?σηkＹＯδO/Ｂº？lＡnaＫ{*Ｋaκ◨+↧aSφ0q‖Ｂ/φx⊘⌕«³ψü✂‹º≡/yc⁴＆Ｊ↙Ｓ²~⎇z§‖$SＰ≧”θＧ↘←¹⁴+⮌⪪θ⸿↑Ｆθ§⁺+-ι⌕-+ιＧ→↙¹⁴-

Provalo online! Il collegamento è alla versione dettagliata del codice. Spiegazione:

ＵＴ

Disattiva il riempimento dello spazio.

≔”...”θ

Assegna una grande stringa compressa composta dalle risposte di @ JonathanAllen per -128.. -15ma con +e -segni trasposti.

Ｇ↘←¹⁴+

Disegna un triangolo di +s del lato 14, che genera i risultati corretti da 1 a 14. Il cursore viene lasciato nell'angolo inferiore, sebbene il ritorno finale sulla stringa compressa sposterà l'uscita successiva sulla riga successiva.

⮌⪪θ⸿

Dividi la stringa grande sui caratteri di ritorno e stampa ogni sottostringa in ordine inverso, generando così i risultati da 15 a 128.

↑

Sposta su una riga in modo che il risultato per 128 sia sovrascritto dal risultato negato per 128.

Ｆθ§⁺+-ι⌕-+ι

Passa attraverso la stringa che traspone +e -torna indietro in modo che generino i risultati corretti per 128-241.

Ｇ→↙¹⁴-

Disegna un triangolo di -s del lato 14, che genera i risultati corretti da 242 a 255.

Gelatina , 1224 + 3716 = 4940 byte

⁾+-ẋ€Ɱ14ZY€U0¦j“6VⱮ×ė7¬(Ị¢ẋṀⱮM⁵Ѭkbvœ⁸½ẋƓ0⁽ṖçḟŻßɓẉḷ0Ƙ¥@ⱮZĊⱮ{ṫṇØ"ỵðẓ⁵!ḳqḄƬiỴƥṇØm@ɗẆḅƥƲ⁴ŀ-5¦€ÑɓZĖ/gPṄḌ!ẹ$ḞıƒĿỵ⁷£Q.%¦ẊiUı-M⁹ƈxṁ,CsḲtÆƇỴṄĿiæEṛⱮẒʠþƘ%ƘƙṾ ('ȥ€½⁵ḥ+,þ@ẇ&ạV|ĊuAYḃfṖƘLƥQtPƬivxHj)Ṇɓ5JṘØẓæĿøɗjḥrñþa®OṅḍṪ¥=ɼġċṫßṬỌƈrUẉçŻ½\=]€ʂ_ⱮṖ¥Ƥȥ6SṡÆcạdn;ṅⱮDɦ⁹ṢAy)~Ḷ`ẒẓMTİṂḋ|ẉ]Wɠ¿⁾Ṣ|ḷ6hẸƒⱮQ1ẏƝC@Ŀ!ʠ⁽ṃ@ƓŒQ3@ƝḊñçcZ\¥3Z¤~çD>ċọuⱮȦAẈⱮ%L3Æ¢ḞtĖė!ƇtñṪɓẓ¥Fṅ⁵shB'wṪẸ¦ṄÞṭ³ʂḶƊ³iȧṂRœŒƤ\r1Çwi6ŀỵɼḃa⁵Ṣ_Q⁸Ẹ'{|\+Æ®|ḤcʂÑ/Ɓz¶ɦÄ!ʂ"Ẋ ẓĠĠ⁷⁵QƝ¶%ṙƇḋ[^j&W×*°ḳçʂSżḊⱮ⁻IȦṄXȥlẋḅ7;⁺ḃİÞÆðLX¢1K£€Ä&X½VȮ(;Q£ḞḢ¹zG+ṅ¹LḥW³ḅd@^ẊḶJ¹T8ṛ($ȧṢzq,Ṫ⁻ȥ{Ṛ"Ḍ®Ä8QḋþɼȮhỵB"Ḍ⁶ȧZ⁵ẒNɓḃȧ¶Ƒð$Ẇ/"Eṭ*I:ØḃL}<KȦ+ṣ¥x&Ṇ£Œṫḋġ0lİḍ¿H£(ỌƝ×^Ḃ°⁽⁼UƭĠḥkQð7ṫƤżȷƘxjƑRḣqƒ$HƬ7ḳ-JµnṇṣðXŻİẉbSu×]bṾ0ƊHßçQh⁸°ƒɦSCñ_⁾ʂC⁼Ġø⁵SAʋƊİ¡⁴ÄḋẸḶwȧZẈĠ7rṀẏẉṖa¤ɱELƝȧẈṣṄk]d⁹øṇÞṡ.ạtƥṢḅ⁺ṂLpÑƘṄṡḍ⁵,Ǥ$Ọ8ṛuṚvAṖÑ1!vƤD3߶ʂа]EÞUĠ€ḋḲ⁸¬r`YḊ0ṙ5ċmṅȯ*ɲU÷pƭẉṭȦB¹ɦSNɱ)]ĠṾʋ³Øḟ23ṭð#ẆuẎṬṫVɠ(ỊỊQɼF}ịƒ$Ẏ_Ṡ'ḳOLc?ṾŀẊẎṆ⁵p"VẏAȮ⁴ⱮȦ®e®Ɱi"ÇJẊ4ñḍḲY]ḌḌẓ⁺ƙ"iṄḅoLṙfOS&}HGɼĖİĠḷuḃ³ṡıḳỊẹzq⁶ƈ£ċHZɱ.#⁶ḟUṗŀȮṘḶḲ]@¶+ḊĖ8ĖṆɗçŻŀ®ṭẇƓḄḷıM@⁷²36ɲṗ¡ḂḊ'Ṿ⁵ėƙṘ-⁺µʠṡṂ[_¤ḥṢ]ṘÐḤ½ḟ4ȷ}E¹Ṙb⁹ḅḢ¹hƬZ§Ẏẹ÷Æ$ḅoĖẉ⁹ịJ.ȥḊẋʋṄȯ1<ẎṄḲṛœ"æ)ḥ8)ḤlñA⁾%⁶LỴ⁶M4Ṙ\`ỵƊȥŀƒ⁷ḌƬƙḳƑ⁴vʂ⁻ðQpñḷḳṄœ>ṪỴƭƙɓ3[&Ḅzḅ<⁾µİṪȧ⁹C>ẹ{ẈÐlC&j?LṆṛ⁽æȤið<⁽$Ḋ7⁻FṡḅɓɱḂJoPŻẆṃṛḂ¹ẓð[1eƘ2T⁶ḟɼ7P~©ṚṙE8RƒṬẹLœẇẸịøḷ*⁾²ÄƓy€VƈɱNSẏẓѶpƲḞḅX⁹ọaœ<aỴTĠ^ðƑṙẊḅOḥŀG4ị¤ÑėÐịʠɗ=YṚċẋĠżẉịṪṁtḳṪ{ṬṃıızD/ĊvȤpḣðСþfÞ⁶ỵỊµṅḷÄ÷Vẇ\Ạ$-§OẠn^ȯfẎlḊd⁶ni¥ẓɱn¶’ṃ“¶><-][+”¤⁷

Un programma completo.

Provalo online!

Come?

Quasi interamente la compressione dei migliori attuali sugli esolang che lasciano solo un singolo diverso da zero, con i movimenti del nastro di trascinamento rimossi. Esiste probabilmente un modo per valutare un sottoinsieme di programmi BF in modo tale da terminare e produrre le soluzioni più brevi che avrebbero battuto questo programma ingenuo. Potrebbe anche esserci un modo per battere questo da un programma più intelligente basato su schemi o sulla fattorizzazione.

⁾+-ẋ€Ɱ14ZY€U0¦j“ ... ’ṃ“¶><-][+”¤⁷ - Link: no arguments
⁾+-                                - list of characters ['+','-']
    €                              - for each:
   ẋ                               -   repeat
     Ɱ14                           -   mapped across [1..14]
        Z                          - transpose
         Y€                        - join each with newline characters
           U0¦                     - reverse the rightmost
                                   -   (now we have ["+\n++\n+++\n ...","... \n---\n--\n-"]
                                ¤  - nilad followed by link(s) as a nilad:
               “ ... ’             -   a really big number compressed as base 250
                       “¶><-][+”   -   list of characters ['\n','>','<','-',']','[','+']
                      ṃ            -   decompress - use as base 7 digits [1,2,3,4,5,6,0]
              j                    - join (the list ["+\n++...","...--\n-"]) with that
                                   - implicit print
                                 ⁷ - a newline character
                                   - implicit print

SuperMarioLang , 231 + 32894 byte

)
))++>(>+)*>[!((&(>[!*>-)-[!([!
===+"="==="=#===="=#="====#==#
+++<(       )    !+< !  ( <
+===+ (   - .    #=" #===="
>[!+( (   !(<
"=#++ (   #="
- (++ !.))    )))            <
) +++ #======================"
+ +++
+ ++!
!+<=#
#="

Provalo online!

Questo sicuramente può essere giocato di più, dato che l'output è il più semplice per Brainfuck, ma mi ci è voluto tutto il giorno per scrivere questa risposta (i miei tre figli mi lasciano poco tempo libero) e sono orgoglioso che almeno sono riuscito a raggiungere Questo.

Python 2, 70 + 8428 = 8498

-2 byte grazie ad A__!
-20 byte Grazie a Jonathan Allan!
-229 byte inserendo il numero nella seconda cella
-1000 byte passando da 16 a 9

p='+'
i=1
exec"print[p*i,i/9*p+'[>'+p*9+'<-]>'+i%9*p][i>20];i+=1;"*255

Provalo online!

Produzione

Rubino 271 + 5363 = 5634

1.upto(255){|n|r=n>(o=n>128?256-n:n)??-:?+;puts o>20?(s=o.to_s(i=(3..9).find{|i|!(s=o.to_s i)[1..-2][s[0]]}).bytes;s[-1]+=s[0]%8;(s[1,9].reverse.map{|c|(c-=s[0])<0??-*-c:c>0??+*c:?-}*?>+'[>'+?+*(s[0]%8)).tr(n>o ?'+-':'','-+')+'[-<'+?+*i+'>]<<]'+(s[-1]>s[0]?'':?>+r)):r*o}

Provalo online!

Converte ogni valore nella base più piccola che non contiene zero della sua cifra iniziale in qualsiasi altro punto, quindi converte da quella base. I valori maggiori di 127 vengono calcolati come loro inverse.

Non avvolgente, 221 + 5888 = 6109

1.upto(255){|n|puts n>20?(s=n.to_s(i=(3..9).find{|i|!(s=n.to_s i)[1..-2][s[0]]}).bytes;s[-1]+=s[0]%8;s[1,9].reverse.map{|c|(c-=s[0])<0??-*-c:c>0??+*c:?+}*?>+'[>'+?+*(s[0]%8)+'[-<'+?+*i+'>]<<]'+(s[-1]>s[0]?'':?>+?-)):?+*n}

Utilizzando lo stesso approccio di cui sopra, con celle non avvolgenti.

Provalo online!

JavaScript (Node.js) , 691 + 3627 = 4318

Utilizzando lo stesso approccio della risposta Charcoal di @ Neil , e quindi basato anche sulla risposta Jelly di @ JonathanAllan .

_=>(a=require('zlib').inflateRawSync(Buffer('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','base64'))+'')+`
--[>-<--]>-
`+[...a.split`
`].reverse().map(s=>s.replace(/[-+]/g,c=>c>','?'+':'-')).join`
`

Provalo online!

Ufficiale Keg 16 + 32895 = 32911 byte

Una soluzione di base per un linguaggio del golf. Questo è il più semplice che mi venga in mente.

ÿï((:|\+$;)_\
')

Provalo online!

Rubino 23 + 32895 = 32918 byte

256.times{|n|puts ?+*n}

Come base. Questa è la soluzione più semplice che mi viene in mente.

Retina 0.8.2 , 28 + 16640 = 16668 byte

127$*+128$*-
\+
¶$`+
-
¶$'-

Provalo online! Include output per 0. Emette solo usando +fino a 127 e -fino a 255.

Scala , 95 + 16639 = 16734 byte

object M extends App{(1 to 127).map(x=>println("+"*x));(0 to 127).map(x=>println("-"*(128-x)))}

Provalo online!

Una risposta semplice che ovviamente non vincerà. Utilizza solo il fatto che l' -operatore (diminuendo un byte) torna a 255.

05AB1E , punteggio: 4848 ( codice sorgente 1219 byte + output 3629 byte)

'+14L×»Â'+'-:•тômG‚ΣP;e3₃ìèÕwƵÜè-½;¨Z±µΛé±V™NkKJžšë₅ušΘ(M₄+ܧ‘мoÕθÚzÇYï#J×¢θýει™₃tQØËв¿U®GƵ´GZ’¯ε¨jjØÛλÄ₅X∍µxθÆvËjS¹∊f˜«VÐZ<ÇĆ’Š2&ØÍäßÍĆlΓV₆ëßê©Œ‡ÛiyĆ=*÷Í´¢‹j,3½íµ'ž4‘û29ôãζм§x…1P|ÛéΣ=~çš5Œ±€Ô“q òǝ?ó¬Æí5¢G‘°êóÿв4LFÍK&zζb2Ó∍æïι8₃4XƵÜÙôt₁‘,Ö…6₅ÞαÇø†c÷Ûλ9…F;ĆA¬iмéλ8ä¶×ƶYΔè¡aû
v=M„ûñ]C₅Õ¶Þ*Ú`Úˆ/₃UιΩW¾eTεvˆ£nYõ¶S¼ÿ{õN9Ω¨£1w‚Ï”Xd;¹OýŒéDнĀvÌ–d=±ΛΣÃÊîD—GR>~ºD‹K¥‘l×yz.éFE1Í©ØM/ƒœOαU‘KΓO‰∍Aм‚œ2нƶþøÌ×¼āHgΩC'Λê¡-߅̾Ā–м–¿<₂δ¡áтgö¬Í~θFíнā‹°ü8[À(xï¸.›*W©¹º₅ÇмδçΛλÉFÕL4†EćÛ´ǝ{тÀ¯†ª™ŽćÉuè¬ƵÀSìFÙη¶1ȸ֛GÜlRv˜jy5mfè∞_åEηŠyo‡xÐ/™¥òÜ#Áx#м6r&₁cÿX۬ƄÌƵ₅∊бγ²Θj∞;6o·¼ýŠΩÚò›c[>ö₅¥=—ªÃ±¿ecSBÐ6Ê!ú¢E¡âìþ߃¿;Ò;„Xoƶ*∍Σǝñ"Tµ†8s®βµ4ìA|«÷γt³+<B¤špTp¸ï7Ëo[>–îiTôó檂?É8zн²ìC1ãl6+ƶå4sЌÚb(°·8ˆ´ˆŸ²ÚÌY3ŸËîÿ‘àUāçh9im„ÝĆm3ŠC×η“åX¨₄|ëPô3O<6Mþ'Ì-s{e`ζQΔ¹œP@l%¥‹èδcsÎcΘÂþ®i₅∞ð¡@`¸¿…BÎN2н>g;ΛSníÐ^Rαθ₆ΣÕ3¹ÐÔCfrQ¦7¨gfŒ|v||þÚÜvz≠pệT˜ǝ=ß·„®¡xи™#?†-Aʒ2åβ₃A¬Ão6ºтõ}Ë.&QηÕ~Δ4€@-5î^a̬.»Èõ4áL¾ò¥n
¶p›éŽžgǝSZγāmεålz₅°dβÂ~λà€Ê%zmŠиˆRη≠éwüǝΛζƵмƶdζ`SÖ₅\≠³äŸj!"(†Üćí“ŠxVöÇe#‡PÏɇ"xð®6ÊεGиe"NÊ›i.k…’Ú8:ǝ/₂ÌÜkãŽo™Áā‚ζΩ«мÁp=}ÂýõλиëÆζиîSÖt¶‚wĀθºd“
₆ŽsLвQ”ÖÜvGõƶiò{÷ÀPy/‹θÑè}¿Á5º˜¯sëØSËƶK_ÍyX∊3Øå4IOθ I+∊ÌñÙçakÞŸŒʒ椱,mεjæ‰O%<ÅtƒVöV=³ÇƶƒC¬‰xðȬM4Ïóä)∍Êfa§õØÂ,“X¾₆₄Ö¦ÈJµÿmȾÎ∍=¡YнŸV!¨J£ü|&¢cUg4e±6w™¼“fÊÙ ,Ž|šP·ùèd}ãŠÅ#GγhYÇN´¼ÁÌMGʒ§Æ1¸‚Δ:j7ΩƵAqá¢<äò´Θ•“-+>][<
“ÅвJs»

L'output è una porta della risposta Charcoal di @Neil , quindi assicurati di votare anche lui!

Provalo online.

Spiegazione:

'+                      '# Push a "+"
  14L                    # Push a list in the range [1,14]
     ×                   # Repeat the "+" that many times as string: ["+","++","+++",...]
      »                  # Join these strings by newlines
       Â                 # Bifurcate it (short for Duplicate & Reverse copy)
        '+'-:            # Replace all "+" for "-"
•тôm...ò´Θ•              # Push compressed integer 18302226724133383998250107335646038608225046109581810887431446835557987256955354954509163336111304735021044106950262344427892947550841899099611054599885158084492762836812161427050275372983896356189873217422270707048679161884382784973706990123491668808316983431947218815813441209357230471947480445527653281307616982417034289994948061000591427114479102114229222423495882782326672492922269629953210111953959859902281658658439835047182218017657439552630082372181376525413759195763958434475193943488791777228373958162363214252781530693967200164833437881609482421594458966138936433283311419810119896020066082377462298326514652481546557215787238749539873039910952003326954299252586309028025200870623285261199142261807190771369911425142504345271105103035478661301795311828767848235694787283635190364512722037791815037475799545052058894119573664059402985074146226606245848663046901585891882552845134633210352731812274795773552227786140415336764040421001184646630833787917147474644077938952053956874031774587527717793206158934471919975714697099518810712871948398923739276321843455690477328633199064849928974478179435369018512187592263559949835435473650276637191671401061097340919482725489354844550472281209666291367830643727358624135371626379451084552903536762775083445643853806852513122856150361979701049267928548063465967555886420646898485890108420374549485423234679327438138302730692296669063696581268627535131608200283731275951916433249161017999011290215932205767570177905442947203826039265793694687731078121685736352831955773450680945121984143563963149079990880719573067270197057276219243821370885160589340870891346257233778661271435191351926058080186177296974642815621539128350975752011448032262905976766027084285390087966682234081285502231618383962136055937741758125210487103109250885525370548106186539295203084216890820183575639032509902729248016346072449636148699098049659529168757116706057794418245039559549604674043961198447420311513558044229534569679723496972989178091506175996419296780639212192856671882116470677803387276814324094247508763467887301684211112080372036284371596072213153957411329532202432808677726223798116216330275138697515009114689489577370759238857602332613821627667530873656034962827810927061440822808985980383150080767015247752949877604372029666921293343149038246728649404223795601960991061986482063744094221616603849190547637439116347239768975065217383194655478092271791087679802480625740835053103772632489195507735140119501008503485917456615266596210333924964188989678201446160111091052524780358620148464886929989973412559470628329156848340802659185674541202787279386158230228148429451357621709967247567009904339076971643378255946241011579618610095231079053137553024558887196808709177094386352264708730475553352082713138948975317023830903305435434148828341201637230241697870602236452176330225025183518037443992277303117971849493548326433875
           "-+>][<\n"    # Push string "-+>][<\n"
                     Åв  # Convert the integer with this string as custom base
                       J # Join all characters together to a single string
s                        # Swap so the triangle of "-" we created it as the top of the stack
 »                       # Join the strings on the stack by newlines
                         # (and output implicitly as result)

Vedere questo suggerimento 05AB1E mio (sezione Come comprimere grandi numeri interi ) per capire il motivo per cui •тôm...ò´Θ•è 183...875.