Come caricare un file nella directory nel bucket S3 utilizzando boto

Voglio copiare un file nel bucket s3 usando python.

Es: ho nome bucket = test. E nel secchio, ho 2 cartelle denominate "dump" e "input". Ora voglio copiare un file dalla directory locale alla cartella "dump" di S3 usando python ... Qualcuno può aiutarmi?

Prova questo...

import boto
import boto.s3
import sys
from boto.s3.key import Key

AWS_ACCESS_KEY_ID = ''
AWS_SECRET_ACCESS_KEY = ''

bucket_name = AWS_ACCESS_KEY_ID.lower() + '-dump'
conn = boto.connect_s3(AWS_ACCESS_KEY_ID,
        AWS_SECRET_ACCESS_KEY)


bucket = conn.create_bucket(bucket_name,
    location=boto.s3.connection.Location.DEFAULT)

testfile = "replace this with an actual filename"
print 'Uploading %s to Amazon S3 bucket %s' % \
   (testfile, bucket_name)

def percent_cb(complete, total):
    sys.stdout.write('.')
    sys.stdout.flush()


k = Key(bucket)
k.key = 'my test file'
k.set_contents_from_filename(testfile,
    cb=percent_cb, num_cb=10)

[AGGIORNAMENTO] Non sono un pythonist, quindi grazie per l'avvertenza sulle istruzioni di importazione. Inoltre, non consiglierei di inserire le credenziali nel tuo codice sorgente. Se lo stai eseguendo all'interno di AWS, utilizza le credenziali IAM con i profili di istanza ( http://docs.aws.amazon.com/IAM/latest/UserGuide/id_roles_use_switch-role-ec2_instance-profiles.html ) e per mantenere lo stesso comportamento in il tuo ambiente Dev / Test, usa qualcosa come Hologram di AdRoll ( https://github.com/AdRoll/hologram )

Non c'è bisogno di renderlo così complicato:

s3_connection = boto.connect_s3()
bucket = s3_connection.get_bucket('your bucket name')
key = boto.s3.key.Key(bucket, 'some_file.zip')
with open('some_file.zip') as f:
    key.send_file(f)

import boto3

s3 = boto3.resource('s3')
BUCKET = "test"

s3.Bucket(BUCKET).upload_file("your/local/file", "dump/file")

L'ho usato ed è molto semplice da implementare

import tinys3

conn = tinys3.Connection('S3_ACCESS_KEY','S3_SECRET_KEY',tls=True)

f = open('some_file.zip','rb')
conn.upload('some_file.zip',f,'my_bucket')

https://www.smore.com/labs/tinys3/

from boto3.s3.transfer import S3Transfer
import boto3
#have all the variables populated which are required below
client = boto3.client('s3', aws_access_key_id=access_key,aws_secret_access_key=secret_key)
transfer = S3Transfer(client)
transfer.upload_file(filepath, bucket_name, folder_name+"/"+filename)

Carica il file su s3 all'interno di una sessione con le credenziali.

import boto3

session = boto3.Session(
    aws_access_key_id='AWS_ACCESS_KEY_ID',
    aws_secret_access_key='AWS_SECRET_ACCESS_KEY',
)
s3 = session.resource('s3')
# Filename - File to upload
# Bucket - Bucket to upload to (the top level directory under AWS S3)
# Key - S3 object name (can contain subdirectories). If not specified then file_name is used
s3.meta.client.upload_file(Filename='input_file_path', Bucket='bucket_name', Key='s3_output_key')

Funzionerà anche:

import os 
import boto
import boto.s3.connection
from boto.s3.key import Key

try:

    conn = boto.s3.connect_to_region('us-east-1',
    aws_access_key_id = 'AWS-Access-Key',
    aws_secret_access_key = 'AWS-Secrete-Key',
    # host = 's3-website-us-east-1.amazonaws.com',
    # is_secure=True,               # uncomment if you are not using ssl
    calling_format = boto.s3.connection.OrdinaryCallingFormat(),
    )

    bucket = conn.get_bucket('YourBucketName')
    key_name = 'FileToUpload'
    path = 'images/holiday' #Directory Under which file should get upload
    full_key_name = os.path.join(path, key_name)
    k = bucket.new_key(full_key_name)
    k.set_contents_from_filename(key_name)

except Exception,e:
    print str(e)
    print "error"   

Questo è un tre linee. Basta seguire le istruzioni sulla documentazione di boto3 .

import boto3
s3 = boto3.resource(service_name = 's3')
s3.meta.client.upload_file(Filename = 'C:/foo/bar/baz.filetype', Bucket = 'yourbucketname', Key = 'baz.filetype')

Alcuni argomenti importanti sono:

Parametri:

import boto
from boto.s3.key import Key

AWS_ACCESS_KEY_ID = ''
AWS_SECRET_ACCESS_KEY = ''
END_POINT = ''                          # eg. us-east-1
S3_HOST = ''                            # eg. s3.us-east-1.amazonaws.com
BUCKET_NAME = 'test'        
FILENAME = 'upload.txt'                
UPLOADED_FILENAME = 'dumps/upload.txt'
# include folders in file path. If it doesn't exist, it will be created

s3 = boto.s3.connect_to_region(END_POINT,
                           aws_access_key_id=AWS_ACCESS_KEY_ID,
                           aws_secret_access_key=AWS_SECRET_ACCESS_KEY,
                           host=S3_HOST)

bucket = s3.get_bucket(BUCKET_NAME)
k = Key(bucket)
k.key = UPLOADED_FILENAME
k.set_contents_from_filename(FILENAME)

Utilizzando boto3

import logging
import boto3
from botocore.exceptions import ClientError


def upload_file(file_name, bucket, object_name=None):
    """Upload a file to an S3 bucket

    :param file_name: File to upload
    :param bucket: Bucket to upload to
    :param object_name: S3 object name. If not specified then file_name is used
    :return: True if file was uploaded, else False
    """

    # If S3 object_name was not specified, use file_name
    if object_name is None:
        object_name = file_name

    # Upload the file
    s3_client = boto3.client('s3')
    try:
        response = s3_client.upload_file(file_name, bucket, object_name)
    except ClientError as e:
        logging.error(e)
        return False
    return True

Per ulteriori informazioni: - https://boto3.amazonaws.com/v1/documentation/api/latest/guide/s3-uploading-files.html

Per esempio di cartella di caricamento come codice seguente e immagine della cartella S3

import boto
import boto.s3
import boto.s3.connection
import os.path
import sys    

# Fill in info on data to upload
# destination bucket name
bucket_name = 'willie20181121'
# source directory
sourceDir = '/home/willie/Desktop/x/'  #Linux Path
# destination directory name (on s3)
destDir = '/test1/'   #S3 Path

#max size in bytes before uploading in parts. between 1 and 5 GB recommended
MAX_SIZE = 20 * 1000 * 1000
#size of parts when uploading in parts
PART_SIZE = 6 * 1000 * 1000

access_key = 'MPBVAQ*******IT****'
secret_key = '11t63yDV***********HgUcgMOSN*****'

conn = boto.connect_s3(
        aws_access_key_id = access_key,
        aws_secret_access_key = secret_key,
        host = '******.org.tw',
        is_secure=False,               # uncomment if you are not using ssl
        calling_format = boto.s3.connection.OrdinaryCallingFormat(),
        )
bucket = conn.create_bucket(bucket_name,
        location=boto.s3.connection.Location.DEFAULT)


uploadFileNames = []
for (sourceDir, dirname, filename) in os.walk(sourceDir):
    uploadFileNames.extend(filename)
    break

def percent_cb(complete, total):
    sys.stdout.write('.')
    sys.stdout.flush()

for filename in uploadFileNames:
    sourcepath = os.path.join(sourceDir + filename)
    destpath = os.path.join(destDir, filename)
    print ('Uploading %s to Amazon S3 bucket %s' % \
           (sourcepath, bucket_name))

    filesize = os.path.getsize(sourcepath)
    if filesize > MAX_SIZE:
        print ("multipart upload")
        mp = bucket.initiate_multipart_upload(destpath)
        fp = open(sourcepath,'rb')
        fp_num = 0
        while (fp.tell() < filesize):
            fp_num += 1
            print ("uploading part %i" %fp_num)
            mp.upload_part_from_file(fp, fp_num, cb=percent_cb, num_cb=10, size=PART_SIZE)

        mp.complete_upload()

    else:
        print ("singlepart upload")
        k = boto.s3.key.Key(bucket)
        k.key = destpath
        k.set_contents_from_filename(sourcepath,
                cb=percent_cb, num_cb=10)

PS: per più URL di riferimento

xmlstr = etree.tostring(listings,  encoding='utf8', method='xml')
conn = boto.connect_s3(
        aws_access_key_id = access_key,
        aws_secret_access_key = secret_key,
        # host = '<bucketName>.s3.amazonaws.com',
        host = 'bycket.s3.amazonaws.com',
        #is_secure=False,               # uncomment if you are not using ssl
        calling_format = boto.s3.connection.OrdinaryCallingFormat(),
        )
conn.auth_region_name = 'us-west-1'

bucket = conn.get_bucket('resources', validate=False)
key= bucket.get_key('filename.txt')
key.set_contents_from_string("SAMPLE TEXT")
key.set_canned_acl('public-read')

Ho qualcosa che mi sembra abbia un po 'più di ordine:

import boto3
from pprint import pprint
from botocore.exceptions import NoCredentialsError


class S3(object):
    BUCKET = "test"
    connection = None

    def __init__(self):
        try:
            vars = get_s3_credentials("aws")
            self.connection = boto3.resource('s3', 'aws_access_key_id',
                                             'aws_secret_access_key')
        except(Exception) as error:
            print(error)
            self.connection = None


    def upload_file(self, file_to_upload_path, file_name):
        if file_to_upload is None or file_name is None: return False
        try:
            pprint(file_to_upload)
            file_name = "your-folder-inside-s3/{0}".format(file_name)
            self.connection.Bucket(self.BUCKET).upload_file(file_to_upload_path, 
                                                                      file_name)
            print("Upload Successful")
            return True

        except FileNotFoundError:
            print("The file was not found")
            return False

        except NoCredentialsError:
            print("Credentials not available")
            return False

Ci sono tre variabili importanti qui, la const BUCKET , il file_to_upload e il file_name

BUCKET: è il nome del tuo bucket S3

file_to_upload_path: deve essere il percorso del file che desideri caricare

file_name: è il file e il percorso risultante nel tuo bucket (qui è dove aggiungi cartelle o altro)

Ci sono molti modi ma puoi riutilizzare questo codice in un altro script come questo

import S3

def some_function():
    S3.S3().upload_file(path_to_file, final_file_name)