Come estrarre 7z zip e avere una struttura di directory corretta?

XXXhostXXX:temp XXXuserXXX$ ls -a dir1/
.   ..  a.txt   b.txt
XXXhostXXX:temp XXXuserXXX$ pwd
/Users/XXXuserXXX/temp
XXXhostXXX:temp XXXuserXXX$ 7z a -t7z dir1 dir1

7-Zip [64] 9.20  Copyright (c) 1999-2010 Igor Pavlov  2010-11-18
p7zip Version 9.20 (locale=utf8,Utf16=on,HugeFiles=on,4 CPUs)
Scanning

Creating archive dir1.7z

Compressing  dir1/a.txt      
Compressing  dir1/b.txt      

Everything is Ok
XXXhostXXX:temp XXXuserXXX$ ls
dir1    dir1.7z
XXXhostXXX:temp XXXuserXXX$ mkdir tmp
XXXhostXXX:temp XXXuserXXX$ mv dir1.7z tmp/.
XXXhostXXX:temp XXXuserXXX$ cd tmp/
XXXhostXXX:tmp XXXuserXXX$ ls
dir1.7z
XXXhostXXX:tmp XXXuserXXX$ 7z e dir1.7z 

7-Zip [64] 9.20  Copyright (c) 1999-2010 Igor Pavlov  2010-11-18
p7zip Version 9.20 (locale=utf8,Utf16=on,HugeFiles=on,4 CPUs)

Processing archive: dir1.7z

Extracting  dir1/a.txt
Extracting  dir1/b.txt
Extracting  dir1

Everything is Ok

Folders: 1
Files: 2
Size:       58
Compressed: 216
XXXhostXXX:tmp XXXuserXXX$ ls
a.txt   b.txt   dir1    dir1.7z
XXXhostXXX:tmp XXXuserXXX$ 
XXXhostXXX:tmp XXXuserXXX$ ls -a dir1
.       ..

Perché alla fine a.txte b.txtsono stati portati fuori dir1?

Sembra che potresti voler provare il comando x invece di e . Per esempio

7za x test.7z

ha funzionato per me e ha conservato le strutture di directory complete